16x^2/y-3/12x^2/3y-9

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Solution for 16x^2/y-3/12x^2/3y-9 equation: 


x in (-oo:+oo)

(16*x^2)/y-((((3/12)*x^2)/3)*y)-9 = 0

(-1/12)*x^2*y+(16*x^2)/y-9 = 0

16*x^2*y^-1-1/12*x^2*y-9 = 0

t_1 = x^2

16*t_1^1*y^-1-1/12*t_1^1*y-9 = 0

16*t_1*y^-1-9 = 0 // + 9

16*t_1*y^-1 = 9 // : 16*y^-1

t_1 = 9/(16*y^-1)

t_1 = 9/(16*y^-1)

x^2-(9/(16*y^-1)) = 0

x^2+(-9/16)*y = 0

1*x^2 = -(-9/16*y) // : 1

x^2 = 9/16*y

x^2 = 9/16*y // ^ 1/2

abs(x) = 3/4*y^(1/2)

x = 3/4*y^(1/2) or x = -(3/4*y^(1/2))

x in { 3/4*y^(1/2), -(3/4*y^(1/2)) }

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